Pembahasan Soal Vektor Matematika Minat X MIPA
Nama : Naila Zia Khalishah
Kelas : X MIPA 2
No. Absen : 28
Link soal : https://lizzanovrida-education.blogspot.com/2021/
28. Vektor u=i-2j-5k, v=-4i+mj-4k, dan w=4i-j+2k. Jika u dan v saling tegak lurus maka hasil dari (u-v).(2w) adalah (40i - 12j - 4k)
Jawab :
Saling tegak lurus maka,
u.v = 0
(i, - 2j, - 5k) . (- 4i, mj, - 4k) = 0
- 4 - 2m + 20 = 0
2m = 4 - 20
2m = - 16
m = - 8
Saling tegak lurus maka,
u.v = 0
(i, - 2j, - 5k) . (- 4i, mj, - 4k) = 0
- 4 - 2m + 20 = 0
2m = 4 - 20
2m = - 16
m = - 8
u - v
= (i, - 2j, - 5k) - (- 4i, mj, - 4k)
= (1, -2, -5) - (- 4, - 8, - 4)
= (5, 6, -1)
2w
= (2) . (4i, - j, 2k)
= (2) . (4, - 1, 2)
= (8, - 2, 4)
= (i, - 2j, - 5k) - (- 4i, mj, - 4k)
= (1, -2, -5) - (- 4, - 8, - 4)
= (5, 6, -1)
2w
= (2) . (4i, - j, 2k)
= (2) . (4, - 1, 2)
= (8, - 2, 4)
(u-v).(2w)
= (5, 6, -1) . (8, - 2, 4)
= (40, - 12, - 4)
(40i - 12j - 4k)
= (5, 6, -1) . (8, - 2, 4)
= (40, - 12, - 4)
(40i - 12j - 4k)
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